One million dollars on the 30th day, it amounts to more than the collective of pennys would.
Answer:
32°
Step-by-step explanation:
Given:
∠DMQ = 58º
In this circle, the radius is DM. Since AD is tangent to the circle M, at point D, and the angle between a tangent and a radius is 90°
Therefore, ∠MDQ = 90°
The total angle in a triangle is 180°. Since we have the values of ∠MDQ and ∠DMQ, ∠DQM will be calculated as:
180 = ∠DMQ + ∠MDQ + ∠DQM
Solving for ∠DQM, we have:
∠DQM = 180 - ∠DMQ - ∠MDQ
∠DQM = 180 - 90 - 58
∠DQM = 32°
The measure of ∠DQM is 32°
Answer:a) L.C.M OF 2,3,5 is 30
THEREFORE=60/30+15/30÷10/30-6/30
=60/30+15/30×30/10-6/30(DMAS)
=60/30+3/2-6/30
=60+45/30 -6/30(ADDITION FIRST THEN SUBTRACTION.
=105/30-6/30
=105-6/30
=99/30
=33/10
b)(3+1/2)÷(2-1/2)=L.C.M IS 2,=(6+1/2)÷(4-1/2)=7/2÷3/2=7/3
Answer:
Step-by-step explanation:
number of cards = 52
number of queen = 4
number of spades = 13
A) probability that the tenth card is a queen
drawn time (r) = 1
position of success(x) = 10th
p = 4/52
P( x,r,p) =
p(10,1,4/52) = 9C0(4/52)^1 * (48/52)^9 = 0.0374
B) probability the twentieth card is a spade
x = 20
r = 1
p = 13 / 52
P(20,1,26/52) = 19C0(26/52)^1 * (26/52)^19 = 0.0010
c) The last five cards been spades
p(last five cards been spades )
p(48..52, 5, 13/52 ) = 47...52C4(13/52)^5 * (39/52)^48..52 - 5
the answer should be 49mm
28*7 / 4 = 49