The range is the ouutput from inputing the input
basically
25=k²+2k+1 and 64=k²+2k+1
the values that satisfy both equations (not at the same tim) are the valuess that are the domain
solve each
25=k²+2k+1
minus 25 both sides (or recognize the perfect square trinomial, but anyway)
0=k²+2k-24
factor
0=(k+6)(k-4)
set to zero
k+6=0
k=-6
k-4=0
k=4
k=-6 or 4
64=k²+2k+1
minus 64 both sides
0=k²+2k-63
facor
0=(k-7)(k+9)
set to zer
k-7=0
k=7
k+9=0
k=-9
k=-9 or 7
so the domain has the numbers
-9,-6,4,7
it seems we only want the positive square roots so
answer is {4,7} is the domain
Answer: Choice A) A true null hypothesis is rejected
In other words, if the reality is that the null is true but your research says otherwise, then you've committed a type i error.
A type ii error is when you fail to reject the null (basically "accepting" the null) while in reality the alternative is the true hypothesis.
Step-by-step explanation:
volume is often quantified numerically using the SI derived unit, the cubic metre.
Answer:
I used a chip bottle and it was 3.5 inches
Step-by-step explanation:
I hope this helps sorry if its wrong
Answer:
15
Step-by-step explanation:
The calculator is actually correct because he entered division before addition.
Following the Bodmas rule of
B= Brackets O= Off D= Division M= Multiplication A= Addition S= Substraction
And from the question 56÷6 + 3 x 2, when bodmas is applied here it becomes ; (56÷6) +( 3 x2)
And when brackets is removed , it becomes
9+6 = 15.