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2 years ago

Please help me please will give brainliest to anyone who is good

Mathematics

2 answers:

hichkok12 [17]2 years ago

5 0

Answer:

Step-by-step explanation:

N = st

Number of toothpicks = (number of students) x (toothpicks)

garri49 [273]2 years ago

3 0

<h3>Answer.</h3>

<h3>Step by step explanation</h3>

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The difference of a number and 6 is the same as 5 times the sum of the number and 2. What is the number?

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2 years ago

The daily production cost, C, for x units is modeled by the equation:

tiny-mole [99]

First find the domain(the set of all first coordinates in a function) by finding where the equation(a mathematical statement that says two expressions have the same value; any number sentence with an = sign) is defined.

After that you should know what to do. I don't know how to work this problem cuz i'm barely in 9 grade. But somehow, I know this.

(−∞,∞)

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If this helped, please let me know and give me brainliest, please!!

If this is incorrect, please let me know so I can fix it!

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2 years ago

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All but one of the following cannot be used internationally

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Answer:

<h2>I think national flag cannot be used internationally</h2>

Step-by-step explanation:

<h2>hope it helps you</h2>

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Round 4.8367 to<br> the thousandths place.

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Find the multiplicative inverse of 6 + 2i

Marina CMI [18]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2774989

________________

Find the multiplicative inverse of

$\mathsf{z=6+2i}$

________

The inverse multiplicative of $\mathsf{z=a+bi}$ is

$\mathsf{\dfrac{1}{z}}\\\\\\
=\mathsf{\dfrac{1}{a+bi}\qquad\quad(a\ne 0~~and~~b\ne 0)}\\\\\\
=\mathsf{\dfrac{1}{a+bi}\cdot \dfrac{a-bi}{a-bi}}\\\\\\
=\mathsf{\dfrac{1\cdot (a-bi)}{(a+bi)\cdot (a-bi)}}\\\\\\
=\mathsf{\dfrac{a-bi}{a^2-\,\diagup\hspace{-10}abi+\,\diagup\hspace{-10}abi-(bi)^2}}$

$=\mathsf{\dfrac{a-bi}{a^2-b^2\cdot i^2}}\\\\\\
=\mathsf{\dfrac{a-bi}{a^2-b^2\cdot (-1)}}\\\\\\
=\mathsf{\dfrac{a-bi}{a^2+b^2}}\\\\\\\\
\therefore~~\mathsf{\dfrac{1}{a+bi}=\dfrac{a}{a^2+b^2}-\dfrac{b}{a^2+b^2}\,i\qquad\quad\checkmark}$

________

For this question,

$\mathsf{z=6+2i}$

So,

$\mathsf{\dfrac{1}{z}}\\\\\\
=\mathsf{\dfrac{1}{6+2i}}\\\\\\
=\mathsf{\dfrac{6}{6^2+2^2}-\dfrac{2}{6^2+2^2}\,i}\\\\\\
=\mathsf{\dfrac{6}{36+4}-\dfrac{2}{36+4}\,i}\\\\\\
=\mathsf{\dfrac{6}{40}-\dfrac{2}{40}\,i}$

$\therefore~~\mathsf{\dfrac{1}{z}=\dfrac{3}{20}-\dfrac{1}{20}\,i}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

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2 years ago

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Please help me please will give brainliest to anyone who is good​

Please help me please will give brainliest to anyone who is good