Answer:
(4x+5)(-3x-1) = -12x²-19x-5
Option A:
(-16x² + 10x - 3) + (4x² - 29x - 2) = -12x²-19x-5
Option A is correct.
Option B:
3(x - 5) - 2(6x² + 9x + 5) = -12x²-15x-25
Option B is wrong.
Option C:
2(x - 1) - 3(4x² + 7x + 1) = -12x²-19x-5
Option C is correct.
Option D:
(2x² - 11x - 9) - (14x² + 8x - 4) = -12x²-19x-5
Option D is correct.
Answer:
A
Step-by-step explanation:
From the graph, we can see that the <em>temperature increased initially</em>, then <em>started to decrease</em>. <u>All of these NOT in a constant rate, though</u>.
Roughly, the temperature was increasing from start till around 5.5 hours. Then on the temperature decreased.
So we can eliminate B, C, and D. That leaves us with correct answer as A.
Answer:
Step-by-step explanation:
x = 1/2 ( a + b)
x = 1/2 (129 + 71)
x = 1/2 (200)
x = 100 °
you just have to remember that formula
Surface area of box=1200 cm²
<span>Volume of box=s²h </span>
<span>s = side of square base </span>
<span>h = height of box </span>
<span>S.A. = s² + 4sh </span>
<span>S.A. = surface area or 1200 cm², s²
= the square base, and 4sh = the four 'walls' of the box. </span>
<span>1200 = s² + 4sh </span>
<span>1200 - s² = 4sh </span>
<span>(1200 - s²)/(4s) = h </span>
<span>v(s) = s²((1200 - s²)/(4s)) </span>
<span>v(s) = s(1200 - s²)/4 . </span>
<span>v(s) = 300s - (1/4)s^3</span>
by derivating
<span>v'(s) = 300 - (3/4)s² </span>
<span>0 = 300 - (3/4)s² </span>
<span>-300 = (-3/4)s² </span>
<span>400 = s² </span>
<span>s = -20 and 20. </span>
again derivating
<span>v"(s) = -(3/2)s </span>
<span>v"(-20) = -(3/2)(-20) </span>
<span>v"(-20) = 30 </span>
<span>v"(20) = -(3/2)(20) </span>
<span>v"(20) = -30 </span>
<span>v(s) = 300s - (1/4)s^3 </span>
<span>v(s) = 300(20) - (1/4)(20)^3 </span>
<span>v(s) = 6000 - (1/4)(8000) </span>
<span>v = 6000 - 2000
v=4000</span>
Answer:
353.35 is the answer of this question
