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2 years ago

Proportional relationships! Need help on!

Mathematics

1 answer:

Jlenok [28]2 years ago

7 0

Direct variation has this equation:

y = kx

where k is the constant of variation

y = -5 ; x = -15

y = kx
-5 = k(-15)
-5/-15 = k
1/3 = k

Choice D. y = 1/3 x

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A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of <em>z</em> for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

2 years ago

One common factor of two numbers is 40. Another common factor is 10. If both numbers are less than 100, what are the two numbers

Viefleur [7K]

Only two numbers less than 100 have a factor of 40: 40 (1 x 40) and 80 (2 x 40). Since 40 is a factor of both 40 and 80, 10 must also be a factor - indeed, 40 = 4 x 10 and 80 = 8 x 10.

The two number must be 40 and 80.

5 0

2 years ago

How do you do this?i need help

DiKsa [7]

Perimeter is the border around something...you add all the sides. So you you'll add 5+5=10 , 8+8=16 , and then you add 10+16=26. The answer is 26.

4 0

2 years ago

Read 2 more answers

The perimeter of a regular hexagon is ninety-six centimetres. Find the length of each side.

rusak2 [61]

Answer:

54cm, which is one side length

Step-by-step explanation:

The sum of all of the sides are 6, it's a regular hexagon the perimemter is just six times one side 36cm

Hope It Helps!

8 0

2 years ago

The product of 7 and a number, all subtracted from 10

expeople1 [14]

Answer: i think the answer is -3

Step-by-step explanation:

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2 years ago