Answer:
D
Step-by-step explanation:
Given the 2 equations
y = x - 5 → (1)
y = x² - 5x + 3 → (2)
Substitute y = x² - 5x + 3 into (1)
x² - 5x + 3 = x - 5 ← subtract x - 5 from both sides
x² - 6x + 8 = 0 ← in standard form
(x - 2)(x - 4) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 2 = 0 ⇒ x = 2
x - 4 = 0 ⇒ x = 4
Substitute each of these values into (1) for corresponding values of y
x = 2 → y = 2 - 5 = - 3 ⇒ (2, - 3 )
x = 4 → y = 4 - 5 = - 1 ⇒ (4, - 1 )
Answer:
Its true
Step-by-step explanation:
For line l to intersect line m at point (2, 1/2), line m must have the point (2,1/2) on its graph. It is implied that line l already has the point (2, 1/2). If line m does not have it, then there will be no intersection at that specific point.
Try checking every choice to see if it has point (2,1/2) on the graph.
Note that (x,y) = (2,1/2); check by using x=2 and y=1/2.
For A,
2x = y/2
2(2) = (1/2) / 2
4 <span>≠ 1/4
</span>
Cannot be choice A as it results in a false equation; this choice will not go through (2,1/2)
For B:
2y = 3 - x
2(1/2) = 3 - 2
1 = 1
This is a true equation so the point (2,1/2) is on the graph of 2y=3-x. This means that if this is the equation for line m, then line m will have a point at (2,1/2) and therefore intersect with line l. Therefore, B is the answer.
The rest of the choices are false as shown:
For C:
2x + 4y = 8
2(2) + 4(1/2) = 8
4 + 2 = 8
6 ≠ 8
Cannot be choice C as it results in a false equation; this choice will not go through (2,1/2)
For D:
y = 4 - (5/4)x
1/2 = 4 - (5/4)(2)
1/2 = 4 - 5/2
1/2 = 8/2 - 5/2
1/2≠ 3/2
Cannot be choice D as it results in a false equation; this choice will not go through (2,1/2)
