Answer:
The function for the outside temperature is represented by ![T(t) = 85\º + 15\º \cdot \sin \left[\frac{t-6\,h}{24\,h} \right]](https://tex.z-dn.net/?f=T%28t%29%20%3D%2085%5C%C2%BA%20%2B%2015%5C%C2%BA%20%5Ccdot%20%5Csin%20%5Cleft%5B%5Cfrac%7Bt-6%5C%2Ch%7D%7B24%5C%2Ch%7D%20%5Cright%5D)
, where t is measured in hours.
Step-by-step explanation:
Since outside temperature can be modelled as a sinusoidal function, the period is of 24 hours and amplitude of temperature and average temperature are, respectively:
Amplitude
Mean temperature
Given that average temperature occurs six hours after the lowest temperature is registered. The temperature function is expressed as:
![T(t) = \bar T + A \cdot \sin \left[2\pi\cdot\frac{t-6\,h}{\tau} \right]](https://tex.z-dn.net/?f=T%28t%29%20%3D%20%5Cbar%20T%20%2B%20A%20%5Ccdot%20%5Csin%20%5Cleft%5B2%5Cpi%5Ccdot%5Cfrac%7Bt-6%5C%2Ch%7D%7B%5Ctau%7D%20%5Cright%5D)
Where:
- Mean temperature, measured in degrees.
- Amplitude, measured in degrees.
- Daily period, measured in hours.
- Time, measured in hours. (where t = 0 corresponds with 5 AM).
If , and 
, the resulting function for the outside temperature is:
Answer:
1) just make an equation (answer below)
SO the new bottle is 30 ounces
The old bottle was 25 percent more then the new one
So we can just find 25 percent of 30
And add it
That is the most simple way but I would just do
30*1.25 Its the same thing but if you think a bout ti, the new bottle can Only hold 30 ounces, 30 ounces is 100 percent of the new bottle, if you multiply 1.25 its adding 25 percent so it Turns a 2 step into a 1 step.
1.25*30=37.5
The larger bottle was 37.5 ounces
The first one since the given measurements/guide is Side, Angle, Side
7.96 / 6 = 1.33 <== unit rate
42.1% of 375.4.....turn percent to decimal...." of " means multiply
0.421(375.4) = 158.0434.....so it would be B. 158.04
