*see attachment for the figure described
Answer:
5 units
Step-by-step explanation:
==>Given the figure attached below, let where FH and EG intercepted be K.
Since FH are midpoints of parallel lines, KE = KG = x.
Given that the area of the kite EFGH = 35 square units, and we know the length of one of the diagonals = HF = KF + KH = 2 + 5 = 7, we can solve for x using the formula for the area of a kite.
Area of kite = ½ × d1 × d2
Where d1 = KH = 7
d2 = EG = KE + KG = x + x = 2x
Area of kite EFGH = 35
THUS:
35 = ½ × 7 × 2x
35 = 1 × 7 × x
35 = 7x
Divide both sides by 7
35/7 = x
x = 5
It shows the Ora scale for area multiply width and length
Answer:
you have done 1/4 ... ....
Answer:
a.$4165
b.$4956.35
Step-by-step explanation:
a)19% × 3500 = 665.
3500+665 =4165
b)19% × 4165 =<u> </u><u>7</u><u>9</u><u>1</u><u>.</u><u>3</u><u>5</u>
<u>4</u><u>1</u><u>6</u><u>5</u><u>+</u><u>7</u><u>9</u><u>1</u><u>.</u><u>3</u><u>5</u><u>=</u><u> </u><u>4</u><u>9</u><u>5</u><u>6</u><u>.</u><u>3</u><u>5</u>