200 volts of current will flow through the conductor.
Answer:
The solutions should be added in this order NaCl > Na2SO4 > Na2S
Explanation:
Silver is insoluble as a chloride, so the silver ions get precipitated on addition of chloride ion as silver chloride. This means Ag+ would be removed the first.
So we will add NaCl in the first step.
The following reaction will occur.
Ag+ + Cl- → AgCl(s)
Both, Pb2 and Ni are soluble as chlorides. (lead chloride is soluble as a hot solution but will ppt when colder).
When we add Na2SO4, Pb2+ will get precipitated (because it's insoluble) as PbSO4 and Ni will remain soluble as NiSO4 is soluble in water.
The reaction that will occur is:
Pb^2+ + SO4^2- → PbSO4(s)
Nickel is insoluble as a sulfide. So when we will add Na2S, nickel will be precipitated as sulfide and be able to separate and be collected.
The solutions should be added in this order NaCl > Na2SO4 > Na2S
Caesium -bluish(Latin) Chlorine -yellow/green (Greek) Iodine -violet (Greek) <span>Rhodium -rose (Greek) Sulphur - yellow (Arabic)</span>
When a substance dissolves, it looks like it disappears. But in fact it has just mixed with the water to make a transparent (see-through) liquid called a solution. A solution has two parts. The solute is the solid that gets dissolved.
The energy of 800 milimoles of photons is 1.38 * 10^-19 J.
<h3>What is excitation of electrons?</h3>
We know that an electron can move from a lower to higher energy level according to the formula;
1/λ = RH(1/ni^2 - 1/nf^2)
RH = 1.097 * 10^7m-1
ni = 3
nf = 6
Thus;
1/λ = 1.097 * 10^7(1/3^2 - 1/6^2)
1/λ = 1.097 * 10^7(1/9 - 1/36)
1/λ = 1.097 * 10^7(0.11 - 0.03)
λ =1.14 * 10^-6 m
v = λf
f = v/λ
f = 3 * 10^8 m/s/1.14 * 10^-6 m
f = 2.6 * 10^14 Hz
Now
E = hf
E= 6.63 * 10^-34 * 2.6 * 10^14 Hz
E = 1.72 * 10^-19 J
Now;
1 mole of photons has 1.72 * 10^-19 J of energy
800 * 10^-3 moles of photons has 800 * 10^-3 moles * 1.72 * 10^-19 J/ 1 mole
= 1.38 * 10^-19 J
Learn more about energy of photons:brainly.com/question/2393994
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