Answers:
a) 
b) 
c) 
d) 46000 s
Explanation:
<h2>a) Time for one cycle of the radio wave</h2>
We know the maser radiowave has a frequency 
of 
In addition we know there is an inverse relation between frequency and time 
:
(1)
Isolating : 
(2)
(3)
(4) This is the time for 1 cycle
<h2>
b) Cycles that occur in 1 h</h2>
If 
and we already know the amount of cycles per second , then:
This is the number of cycles in an hour
<h2>c) How many cycles would have occurred during the age of the earth, which is estimated to be
?</h2>
Firstly, we have to convert this from years to seconds:
Now we have to multiply this value for the frequency of the maser radiowave:
This is the number of cycles in the age of the Earth
<h2>
d) By how many seconds would a hydrogen maser clock be off after a time interval equal to the age of the earth?</h2>
If we have 1 second out for every 100,000 years, then:
This means the maser would be 46000 s off after a time interval equal to the age of the earth
Answer:
Light
Explanation:
The way a concave mirror works is that since it's concave, the light bounces off of each other. a convex mirror, it curved the opposite, and the mirror has no way to bounce off of itself.
Answer:
b. slow-moving streams.
Explanation:
In Fluid Mechanics, the Reynolds numbers indicates the existence of turbulence in fluid streams. Low Reynolds numbers are related with laminar flow. The Reynolds formula is:
The Reynolds number is directly proportional to fluid speed. Hence, slow-moving streams are a sound example of laminar flow. The correct answer is B.
Answer:
a) 11 m/s
b) 0.0564 s
Explanation:
Given:
m = 2100 kg
vi = 22 ..... m/s before collision
vf = 0 ......after collision to stop
Δs = 0.62 distance traveled after collision .. crumpling of truck
Part a
Part b
The speed of tsunami is a.0.32 km.
Steps involved :
The equation s = 356d models the maximum speed that a tsunami can move at. It reads as follows: s = 200 km/h d =?
Let's now change s to s in the equation to determine d: s = 356√d 200 = 356√d √d = 200 ÷ 356 √d = 0.562 Let's square the equation now by squaring both sides: (√d)² = (0.562) ² d = (0.562)² = 0.316 ≈ 0.32
As a result, 0.32 km is roughly the depth (d) of water for a tsunami moving at 200 km/h.
To learn more about tsunami refer : brainly.com/question/11687903
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