How do you find the remainder of (x^3-6x^2-9x+3) / (x-3)
1 answer:
You might be interested in
Answer:
Either a can be 0 or 10/3
Step-by-step explanation:
Given that a right triangle has vertices as (6,2) and we have to find the third vertex on the y axis
Since the third vertex lie on y axis, it would have coordinates as (0,a)
Using slope formula we can say one pair of sides will be perpendicular
Let A (6,2) B (5,5) and C (0,a)
Slope of AB = change in y coordinate /change in x coordinate = -3
Slope of BC =
Slope of CA =
If AB and BC are perpendicular then
... i
OR if BC and CA are perpendicular then,
(a-5)(a-2)= -30
No real roots
OR if CA and AB are perpendicular
(a-2) =-2
a=0
Either a can be 0 or 10/3