Answer:
○![\displaystyle -\frac{2\sqrt{3}}{3}\:[or\:-\frac{2}{\sqrt{3}}]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20-%5Cfrac%7B2%5Csqrt%7B3%7D%7D%7B3%7D%5C%3A%5Bor%5C%3A-%5Cfrac%7B2%7D%7B%5Csqrt%7B3%7D%7D%5D)
Step-by-step explanation:
You have to know the Unit Circle on this one. So, to start off, in the degree-angle range from 180° - 270° [Quadrant III], you must figure out the cosine value that gives you −½, and according to the graph, <em>theta</em><em> </em>will be represented as 240°. So, now that we have our <em>θ</em>, looking at the <em>y-value</em><em> </em>240°, since we want the <em>cosecant</em><em> </em>function, all we have to do is take the multiplicative inverse of 
which gives you 
Extended Information
![\displaystyle -\frac{2\sqrt{3}}{3} = [-\frac{\sqrt{3}}{2}]^{-1}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20-%5Cfrac%7B2%5Csqrt%7B3%7D%7D%7B3%7D%20%3D%20%5B-%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%5D%5E%7B-1%7D)
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Answer:
32 ft
Step-by-step explanation:
Given data
Length= 8ft
Area= 64 f^2
Let us find the width
Area= Length*Width
64= 8* Width
Width= 64/8
Width= 8ft
Hence the perimeter= 2L+2W
P= 2*8+2*8
P= 16+16
P= 32 ft
Answer:
Step-by-step explanation:
A grocery store has a 13%-off sale on all bread.
Let b represent the original price of a loaf of bread.
This means that the amount by which the price of bread was reduced would be
13/100 × b = 0.13 × b = 0.13b
The new price for the loaf of bread would be
b - 0.13b
you decide to purchase 6 loaves of bread. The expression would be
6(b - 0.13b)
Expanding the expression, it becomes
6b - 0.78b
Answer: If we define 2:00pm as our 0 in time; then:
at t= 0. the velocity is 30 mi/h.
then at t = 10m (or 1/6 hours) the velocity is 50mi/h
Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:
a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/
Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)
So if v is differentiable, then there is a time T between 0h and 1/6h where v(T) = 120mi/
