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If M∠ ABD =64 and M∠CBD=30 then M∠ABC= <br> Need help

Leno4ka [110]

Answer:

$\displaystyle m\angle ABC = 34^\circ$

Step-by-step explanation:

∠ABD is the sum of the angles ∠ABC and ∠CBD. In other words:

$\displaystyle m\angle ABD = m\angle ABC + m\angle CBD$

Substitute in known values:

$\displaystyle \left(64^\circ\right) = m\angle ABC + \left(30^\circ\right)$

And subtract. Hence:

$\displaystyle m\angle ABC = 34^\circ$

In conclusion, ∠ABC measures 34°.

4 0

2 years ago

ME AYUDAN?? ¨Carlos compró un automóvil nuevo por un valor de $39000. Cada año que pasa desde la compra el auto disminuye su val

MrRa [10]

Multiplica 30 por 1500

Luego resta el resultado de la multiplicación por 39000 y te da el resultado de nada

3 0

2 years ago

What is 3.12 x 0.25???

Mamont248 [21]

Answer:

0.78

Step-by-step explanation:

0.78 is 25% of 3.12

to check just multiply 0.78 by 4

0.78*4=3.12

3 0

1 year ago

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What is the inverse of f(x) =

Katen [24]

Answer:

1

--------- is the inverse of f(x)

2x - 2

5 0

2 years ago

The temperature of a cup of coffee varies according to Newton's Law of Cooling: dT dt equals negative k times the quantity T min

dolphi86 [110]

This is a doozy. I actually have another form of the equation for cooling, and it's in Celcius (so I convert) and seconds (we can switch back to minutes in the end). The Celcius and Fahrenheit don't matter because it's the time we are interested in and as long as we use the C and F equivalents, we're fine. Promise. The formula is as follows: $T(t)= T_{s}+( T_{0}- T_{s})e ^{-kt}$ . It's really easy to use. T(t) is the ending temperature; $T_{s}$ is the room temp; $T_{0}$ is our initial temperature of the liquid; e is Euler's number, k is the constant of variation, and t is the time in seconds. In Celcius, our temps are as follows: 180 F = 82.2 C; 100 F = 37.8 C; 75 F = 23.9 C; 80 F = 26.7 C. 10 minutes is 600 seconds. Filling in our formula with all of that, we will solve for k. Then we will use that k value to solve for the time in the question we are told to answer. Let's do this. $37.8=23.9+(82.2-23.9)e ^{-600k}$ . Simplifying a bit we have $37.8=23.9+(58.3)e ^{-600k}$ . Subtracting 23.9 from both sides we have $13.9=58.3e ^{-600k}$ . divide both sides by 58.3 to get $.2384219=e ^{-600k}$ . At this point in your mathematical career, I'm assuming that since you're doing this, you're studying natural and common logs. The base of a natural log is e, therefore, if we take the natural log of e, they both "undo" each other and cancel each other out completely. So let's do that. $ln(.2384219)=-600k$ . Simplifying on the left gives us $-1.433713=-600k$ . Dividing both sides by -600 gives us a k value of .002389. Now we will do the equation again, using that k value, to solve for how long it takes for the coffee to cool to 80 F (26.7 C). $26.7=23.9+(82.2-23.9)e ^{-.002389t}$ . Simplifying a bit again gives us $26.7=23.9+(58.32)e ^{-.002389t}$ . Subtracting 23.9 from both sides gives us $2.8=(58.32)e ^{-.002389t}$ . We will now divide both sides by 58.32 to get $.0480109=e ^{-.002389t}$ . Again we will take the natural log of both sides to "undo" the e: $ln(.0480109)=-.002389t$ . The natural log of .0480109 is -3.036325671. So, dividing both sides by the negative decimal on the right gives us $\frac{-3.036325671}{-.002389}=t$ and t = 1270.9 seconds. Divide that by 60 to get the time in minutes. t = 21.1826...so 21 minutes. Phew!!!

7 0

2 years ago

Read 2 more answers