Answer:
y-1=2(x+4) or y=2x+9
Step-by-step explanation:
y - 3 = 2(x + 7)
y=mx+b
m=2
(x1,y1) -> (-4, 1)
(y−y1)=m(x−x1)
plug in
y-1=2(x+4)
y-1=2x+8
y=2x+9
test:
(1)=2(-4)+9
1=-8+9
1=1
Answer:
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Step-by-step explanation:
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9514 1404 393
Answer:
Step-by-step explanation:
In the left problem, you use the fact that <em>the sum of the segment lengths is equal to the overall length</em>.
AC +CB = AB
(3x -4) +(x -2) = 62
4x -6 = 62 . . . . . collect terms
4x = 68 . . . . . . . add 6
x = 17 . . . . . . . . . . divide by 4
__
In the right problem, you use the fact that <em>the sum of the angles is equal to the overall angle</em>. Here, that overall angle is a linear angle, so measures 180°.
∠DFG +∠GFE = ∠DFE
(5y +3) +(2y -5) = 180
7y = 182 . . . . . . . . . . . . . . collect terms, add 2
y = 26 . . . . . . . . . . . . . . . .divide by 7
Answer:
Step-by-step explanation:
No, the equation cannot be written with the given information. The distance from the catapult when the watermelon reached the maximum height is needed. Since the watermelon did not start on the ground, it cannot be assumed that the maximum was reached half the distance to the landing point.
L*w=area
(3x+21)*w=3x^2+33x+84
w=(3x^2+33x+84)/3x+21
(3(x+4)(x+7))/3(x+7)
w=x+4
