The momentum of a 5kg object that has a velocity of 1.2m/s is 6.0kgm/s.
<h3> MOMENTUM:</h3>
Momentum of a substance is the product of its mass and velocity. That is;
Momentum (p) = mass (m) × velocity (v)
According to this question, an object has a mass of 5kg and velocity of 1.2m/s. The momentum is calculated thus:
Momentum = 5kg × 1.2m/s
Momentum = 6kgm/s.
Therefore, the momentum of a 5kg object that has a velocity of 1.2m/s is 6.0kgm/s.
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Answer:
The average recoil force on the gun during that 0.40 s burst is 45 N.
Explanation:
Mass of each bullet, m = 7.5 g = 0.0075 kg
Speed of the bullet, v = 300 m/s
Time, t = 0.4 s
The change in momentum of an object is equal to impulse delivered. So,
For 8 shot burst, average recoil force on the gun is :
So, the average recoil force on the gun during that 0.40 s burst is 45 N.
Under the assumption that the three rocks are dropped from the same height, they will hit the ground at the same speed. The gravity of Earth is virtually the same for any object that is small compared to the size of the Earth. The acceleration will change with the distance from the Earth, but this change is so small for the range of heights we work with (consider the range of heights from sea level to the tip of Mount Everest) that we can take the average value and assume it to be constant. This constant value of acceleration due to Earth's gravity is 9.80665m/s²
Because the objects fall under the same constant acceleration, they will hit the ground at the same speed.