2 years ago

What ia measurement in science

1 answer:

8 0

Answer:

In science, a measurement is quantitative (in terms is which is heavier, lighter, fast, slow and all) or numerical data(numbers like 1m,1cm) that describes a property of an object or event.

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Solve for x -6x + 7 > 1

Elenna [48]

the answer is 6/5

-5x>-6

x>-6/-5

x>6/5

5 0

3 years ago

Read 2 more answers

The domain of both

Margarita [4]

Answer:

The domain of function $h(x)$ is set of all real numbers.

Domain: (-∞,∞)

Step-by-step explanation:

Given:

$f(x)=x-6$

$g(x)=x+6$

the domain of both the above functions is all real number.

To find domain of :

$h(x)=f(x)g(x)$

Substituting functions $f(x)$ and $g(x)$ to find $h(x)$

$h(x)=(x-6)(x+6)$

The product can be written as difference of squares. $[a^2-b^2=(a+b)(a-b)]$

∴ $h(x)=x^2-36$

The degree of the function $h(x)$ is 2 as the exponent of leading term $x^2$ is 2. Thus its a quadratic equation.

For any quadratic equation the domain is set of all real numbers.

So Domain of $h(x)$ is (-∞,∞)

7 0

2 years ago

H(x)=1/8x^3-x^2<br><br> Over which interval does h have a positive average rate of change?

lara31 [8.8K]

Answer:

$(-\infty,0)\cup(\frac{16}{3},\infty)\\That \ is x\frac{16}{3}$

Step-by-step explanation:

$h(x)=\frac{1}{8}x^{3} -x^{2} \\\\Differentiate \ h(x) \ with \ respect \ to \ x\\h'(x)=\frac{3}{8}x^{2} -2x$

For positive rate of change $h'(x)>0$

$\frac{3}{8} x^{2} -2x>0\\x(\frac{3}{8}x-2)>0\\\\ When \ x0 \ (multiplication \ of \ two \ positives \ is \ positive)\\\\h'(x)>0 \ when \ x\frac{16}{3} \\\\$