Answer:
p =5
Step-by-step explanation:
3p − 5 = 10
Add 5 to each side
3p-5+5 =10+5
3p = 15
Divide each side by 3
3p/3 = 15/3
p =5
The probability that the lock code will begin with the number 5 is; 1/9 while the probability that the code will not contain the number 0 is; (8/9)³.
<h3>What is the probability that the lock code will begin with the number 5?</h3>
It follows from the task content that the probability of different scenarios of the lock code.
The probability that the lock code will begin with the number 5 is; 1/9 following from the definition of probability as the ratio of the number of required outcome to the number of possible outcomes.
Read more on probability;
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Answer:
8/11.
Step-by-step explanation:
There are a total of 11 balls.
At least one of those picked is green means that 1 or 2 green balls are picked in the two trials.
Prob (First one picked is green) = 5/11.
Prob( second one picked is green) = 4/10 = 2/5.
Therefore Prob ( Green then green) = 5/11 * 2/5 = 10/55 = 2/11.
The other possibilities are Green then Yellow OR Yellow then Green.
The probabilities of these are worked out as above and come to
5/11 * 6/10 and 6/11 * 5/10
= 300/110 and 30/110
= 3/11 and 3/11.
Finally the Prob ( 2G OR G&Y OR Y&G) = 2/11 + 3/11 + 3/11
= 8/11.
I just realised there is an easier way to do this. Much less work.
The only other thing that can happen other than ' at least one green' is '2 yellows' so the required probability is
1 - prob(2 yellows)
= 1 - (6/11 * 5/10)
= 1 - 30 /110)
= 1 - 3/11
= 8/11.
But never mind. I hope the above is instructive and helps you understand.
Answer:
13t+5
Step-by-step explanation:
Answer:
23?
Step-by-step explanation: