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2 years ago

Which best represents data that is not likely to be clustered?

Mathematics

1 answer:

AfilCa [17]2 years ago

6 0

Answer: guess it your self

Step-by-step explanation:

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During a visit to the tide pools, Brent observed 16 sea stars, 4 sea urchins, and 52 sea anemones. What is the ratio of sea anem

weeeeeb [17]

Answer:

16 to 52

Step-by-step explanation:

7 0

1 year ago

The length of a rectangle is 3 times the width.If the length is decreased by 4 m and the width is increased by 1 m , the perimet

o-na [289]

Answer:

Length = 27 metres

Width = 9 metres

Step-by-step explanation:

Consider the width to be x.

Then the length will be 3x.

The perimeter is 66m when the width is increased by 1m and the length is decreased by 4m.

So the dimensions will become:

Length=3x-4

Width=x+1

Now solve for the variable x using the formula for perimeter of a rectangle:

P = 2(l+b)

66 = 2(3x-4+x+1) (Divide both sides by 2 and simplify the parentheses)

33 = 4x-3 (Add 3 to both sides)

36 = 4x (Divide both sides by 4)

x = 9

Now plug-in the value of x into the original dimensions which were:

Length=3x

Width=x

So the dimensions are:

Length = 27 metres

Width = 9 metres

6 0

2 years ago

The vertex form of the equation of a parabola y=(x-3)^+36

MrMuchimi

Answer:

ewrwewqetqwrtweq

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

What is the value of 5^3i^9?

Yakvenalex [24]

Answer:

$\displaystyle 125^i$

Step-by-step explanation:

Extended Information on the Complex Number System

$\displaystyle \sqrt{-1} = i \\ -1 = i^2 \\ -i = i^3 \\ 1 = i^4\:[all\:multiples\:of\:four]$

I am joyous to assist you at any time.

All work is shown above. ↑

4 0

2 years ago

Find the x-intercepts of the parabola with vertex (1,-108) and y-intercept (0,-105). Write your answer in this form: (X1,y1), (x

Stolb23 [73]

Answer:

(7, 0) and (-5, 0)

Step-by-step explanation:

Vertex form

$y=a(x-h)^2+k$

(where (h, k) is the vertex)

Given:

vertex = (1, -108)

$\implies y=a(x-1)^2-108$

Given:

y-intercept = (0, -105)

$\implies a(0-1)^2-108=-105$

$\implies a(-1)^2=-105+108$

$\implies a=3$

Therefore:

$\implies y=3(x-1)^2-108$

The x-intercepts are when y = 0

$\implies 3(x-1)^2-108=0$

$\implies 3(x-1)^2=108$

$\implies (x-1)^2=36$

$\implies x-1=\pm \sqrt{36}$

$\implies x=1\pm 6$

$\implies x=7, x=-5$

Therefore, the x-intercepts are (7, 0) and (-5, 0)

7 0

1 year ago