Y = -15 is the answer and blah
Answer:
It's heavy cream
Step-by-step explanation:
Homogenized milk has a density of 1.032 kg/L and
heavy cream has a density of 1.005 kg/L at 10°C.
At 10°C, a container holding 8 liters of liquid weighs 8.04 kilograms
To determine which container hold homogenized milk or heavy cream and How I know?
We findo the density of the measurements given and whatever it correspond to is what it is
First mass is 8.04kg
Liquid contained is 8 litres
SInce the density is kg/L
No need for conversion
Density = mass/volume = 8.04/8= 1.005kg/L
Heavy cream has a density of 1.005 kg/L at 10°C.
Therefore it correspond
Answer:
28 dollars is the new price.
Step-by-step explanation:
Find the horizontal and vertical distance between the points. First, subtract y2 - y1 to find the vertical distance. Then, subtract x2 - x1 to find the horizontal distance.
Answer:
The x-coordinate of the point changing at ¼cm/s
Step-by-step explanation:
Given
y = √(3 + x³)
Point (1,2)
Increment Rate = dy/dt = 3cm/s
To calculate how fast is the x-coordinate of the point changing at that instant?
First, we calculate dy/dx
if y = √(3 + x³)
dy/dx = 3x²/(2√(3 + x³))
At (x,y) = (1,2)
dy/dx = 3(1)²/(2√(3 + 1³))
dy/dx = 3/2√4
dy/dx = 3/(2*2)
dy/dx = ¾
Then we calculate dx/dt
dx/dt = dy/dt ÷ dy/dx
Where dy/dx = ¾ and dy/dt = 3
dx/dt = ¾ ÷ 3
dx/dt = ¾ * ⅓
dx/dt = ¼cm/s
The x-coordinate of the point changing at ¼cm/s
