Answer: (0,-1/2)
Step-by-step explanation:
Edge :-)
Answer:
16.17684994
Step-by-step explanation:
First diagonal
x^2 = a^2 + b^2
x^2 = 5^2 + 6^2
x^2 = 61
x ≈ 7.810249676
Second diagonal
x^2 = a^2 + b^2
x^2 = 7.810249676^2 + 3^2
x^2 = 70
x ≈ 8.366600265
Sum of both diagonals
8.366600265 + 7.810249676
= 16.17684994
Answer:
x=-4 y=-1
Step-by-step explanation:
Let's solve your system by substitution.
−3x−8y=20;y=5x+19
Rewrite equations:
y=5x+19;−3x−8y=20
Step: Solve y=5x+19for y:
y=5x+19
Step: Substitute5x+19foryin−3x−8y=20:
−3x−8y=20
−3x−8(5x+19)=20
−43x−152=20(Simplify both sides of the equation)
−43x−152+152=20+152(Add 152 to both sides)
−43x=172
−43x
−43
=
172
−43
(Divide both sides by -43)
x=−4
Step: Substitute−4forxiny=5x+19:
y=5x+19
y=(5)(−4)+19
y=−1(Simplify both sides of the equation)
Answer:
x=−4 and y=−1
Answer:
The option "StartFraction 1 Over 3 Superscript 8" is correct
That is 
is correct answer
Therefore ![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2%3D%5Cfrac%7B1%7D%7B3%5E8%7D)
Step-by-step explanation:
Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared
The given expression can be written as
![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2)
To find the simplified form of the given expression :
( using the property 
)
( using the property 
( combining the like powers )
( using the property 
)
( using the property 
)
Therefore
Therefore option "StartFraction 1 Over 3 Superscript 8" is correct
That is is correct answer
Answer:
The answer is D.
Step-by-step explanation:
H(o): p=0.50, H(a): p greater than 0.50
(sorry couldn't type of the greater than sign symbol)
