That is a question about perimeter of rectangle.
The perimeter of a geometric shape is the sum of the value of the all sides.
In a rectangle, the opposite sides are cogruentes (equals). For example, look at picture below. In that rectangle, the sides AB and DC are equals, and the sides AD and BC are equals.
So, the sides of that rectangular table are: 1.52m, 1.52m, 0.75m and 0.75.
Therefore, the perimeter of that rectangle is 
m.
But that is not the final answer because that is the perimeter in meters and the question want the answer in centimeters.
1 meter has 100 centimeter, so we need to multiplicate the perimeter by 100.
Thus, the perimeter of that rectangular table is 
cm.
Answer:
<u>375 Adult Tickets.</u>
Step-by-step explanation:
Here, we can simply set up an equation using variable <em>x </em>in place of the unknown student/adult tickets.
x = # of <u>adult</u> tickets sold
x + 65 = # of <u>student</u> tickets sold.
1) x + x + 65 = 815 (set both ticket amounts equal to the total)
2) 2x + 65 = 815 (added common variables together)
3) 2x = 750 (negated the +65, subtracted it from both sides)
4) x = 375 (divided both sides by 2)
5) 815 - 375 = 440 (subtracted the x from the total number of <u>adult</u> tickets, to recieve the amount of <u>childrens</u>' tickets.
Therefore,
Since there were fewer adult tickets sold (-65), 375 is the number of adult tickets, and 440 is the number of student tickets.
Answer:
221
Step-by-step explanation:
Day 8 is the first day of the second week.
Day 21 is the last day of week 3.
We need to know the n umber of bicycles made from t = 1 to t = 3
The function is b(t) = 110 + 0.5t^2 - 0.9t, where t is in weeks.
We need to integrate the function with the limits of 1 to 3.
Answer: 221
If you're asking for the measurements, they are...
Length (l) = 4 ft.
Width (w) = 4 ft.
Height (h) = 4 ft.
Answer:
1. 15x^7y^2 + 4x^3 => x^3(15x^4y^2 + 4)
2. 15x^7y^2 + 3x => 3x(5x^6y^2 + 1)
3. 15x^7y^2 + 6xy => 3xy(5x^6y + 2)
4. 15x^7 + 10y^2 => 5(3x^7 + 2y^2)
Step-by-step explanation:
To obtain the answer to the question, first let us factorise each expression. This is illustrated below:
1. 15x^7y^2 + 4x^3
Common factor is x^3, therefore the expression is written as:
x^3(15x^4y^2 + 4)
2. 15x^7y^2 + 3x
Common factor is 3x, therefore the expression is written as:
3x(5x^6y^2 + 1)
3. 15x^7y^2 + 6xy
Common factor is 3xy, therefore the expression is written as:
3xy(5x^6y + 2)
4. 15x^7 + 10y^2
Common factor is 5, therefore the expression can be written as:
5(3x^7 + 2y^2)
