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2 years ago

Which of the following ordered pair could NOT be included in this set if it is a function?

Mathematics

1 answer:

AlexFokin [52]2 years ago

4 0

Answer:

B is the right answer and if you add

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Which angle in the figure is a right angle?

weeeeeb [17]

Answer:

∠TUS I'm pretty sure because t and u make a right angle

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1 year ago

Before beginning voice lessons, Colin already knew how to sing 2 pieces, and he expects to

Vsevolod [243]

Answer: Answer is 24 though

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2 years ago

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The angle of a quadrilateral are A.P and the common difference is 10°. find the angles.

xxMikexx [17]

Step-by-step explanation:

So the Ap will be x,x+10,x+20,x+30

Sum of the angles of a quadrilateral is 360

x+x+10+x+20+x+30=360

4x+60=360

4x=300

x=75

So the angles are 75,85,95,105

4 0

2 years ago

Graph the equation y= -4/3x+2

Nadya [2.5K]

Answer:

Step-by-step explanation:

I attached a graph.

Hope that helps!

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1 year ago

URGENT: If θ is a second-quadrant angle and cosθ = -2/3, then tanθ = _____.

dangina [55]

In the second quadrant, both cos and tan are negative while only sin is positive.

To find tan, we will use the following property below:

$\large \boxed{ {tan}^{2} \theta = {sec}^{2} \theta - 1}$

Sec is the reciprocal of cos. If cos is a/b then sec is b/a. Since cos is 2/3 then sec is 3/2

$\large{ {tan}^{2} \theta = {( - \frac{3}{2}) }^{2} - 1} \\ \large{ {tan}^{2} \theta = \frac{9}{4} - 1} \\ \large{ {tan}^{2} \theta = \frac{9}{4} - \frac{4}{4} \longrightarrow \frac{5}{4} } \\ \large{tan \theta = \frac{ \sqrt{5} }{ \sqrt{4} } } \\ \large \boxed{tan \theta = \frac{ \sqrt{5} }{2} }$

Since tan is negative in the second quadrant. Hence,

$\large{ \cancel{ tan \theta = \frac{ \sqrt{5} }{2} } \longrightarrow \boxed{tan \theta = - \frac{ \sqrt{5} }{2} }}$

Answer

tan = -√5/2

3 0

2 years ago