Answer:
A sample size of 6755 or higher would be appropriate.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The margin of error M is given by:
90% confidence level
So , z is the value of Z that has a pvalue of , so .
52% of Independents in the sample opposed the public option.
This means that
If we wanted to estimate this number to within 1% with 90% confidence, what would be an appropriate sample size?
Sample size of size n or higher when . So
A sample size of 6755 or higher would be appropriate.
Answer:
B
Step-by-step explanation:
-1/2
Answer:
Step-by-step explanation:
For this case we have the following data given:
2.3 3.1 2.8
1.7 0.9 4.0
2.1 1.2 3.6
0.2 2.4 3.2
Since the data are assumedn normally distributed we can find the standard deviation with the following formula:
And we need to find the mean first with the following formula:
And replacing we got:
And then we can calculate the deviation and we got:
Answer:
d^2 = 30^2 + 12^2
e^2 = d^2 + 8^2
e^2 = 30^2 + 12^2 + 8^2
e = √(30^2 + 12^2 + 8^2) = 33.3 ft
Answer:
x = √30
Step-by-step explanation:
From small triangle BDC:
using Pythagorean theorem
CB² = BD² + DC²
x² = BD² + 3²
Fron triangles BDC and ADB.
ΔBDC has long leg BD and short leg DC.
ΔADB has long leg AD and shirt leg BD.
AD : BD = BD : DC
7 : BD = BD : 3
7*3 = BD*BD
BD² = 7*3 = 21
x² = BD² + 3² = 21+9 = 30
x² = 30
x = √30