Well, a distance-preserving transformation is called a rigid motion, and the name suggests that it <em>moves the points of the plane around in a rigid fashion.</em>
A transformation is distance-preserving if the distance between the images of any two points and the distance between the two original points are equal.
If that's confusing, I get it; basically if you transform something, the points from the transformation are image points. Take the distance from a pair of image points, and take the distance from a pair of original points, and they should be the same for a <em>rigid </em>motion.
I keep emphasizing this b/c not all transformations preserve distance; a dilation can grow or shrink things. But if you didn't go over dilations, don't say nothin XD
-0.5 n^2=-18
n^2= 36
n= sqrt (36)=6 or -6
Hope this can help.
<span><span> </span><span>Steps:<span>Divide the decimal number by 16. Treat the division as an integer division. Write down the remainder (in hexadecimal).Divide the result again by 16. Treat the division as an integer division. Repeat step 2 and 3 until result is 0.<span>The hex value is the digit sequence of the remainders from the last to first.</span></span></span></span>
<span>3 is 1.0 below the mean. That is 1.0 / 0.9, or 1.1111... standard deviations below the mean.
So look up z < -1.11 on your graphing calculator.
It should be around 0.1335 or 13.35%</span>