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2 years ago

Allen has a 75 yard spool of yarn. He needs to cut the spool of yarn into 6 1/4

Mathematics

2 answers:

netineya [11]2 years ago

5 0

Answer:

b (12)

Step-by-step explanation:

Gwar [14]2 years ago

4 0

Answer:

B. 12 pieces

Step-by-step explanation:

75 / 6 1/4 or 75 / 6.25 = 12

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5/8 herself + friends

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2 years ago

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Jessica is collecting aluminum cans during the summer for a recycling project. She collected 120 aluminum cans in June and 150 a

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Proponents of rational expectations theory argued that, in the most extreme case, if policymakers are credibly committed to redu

jarptica [38.1K]

Answer:

The answer is zero or option D.

Step-by-step explanation:

Proponents of rational expectations theory argued that, in the most extreme case, if policymakers are credibly committed to reducing inflation and rational people understand that commitment, and quickly lower their inflation expectations, the sacrifice ratio could be as small as 0.

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2 years ago

Find the values of x and y.

kotykmax [81]

Answer:

y=9 and x=18

Step-by-step explanation:

You know that y+3=12 so 12-3=9

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2 years ago

The daily revenues of a cafe near the university are approximately normally distributed. The owner recently collected a random s

lbvjy [14]

Answer:

The sample size to obtain the desired margin of error is 160.

Step-by-step explanation:

The Margin of Error is given as

$MOE=z_{crit}\times\dfrac{\sigma}{\sqrt{n}}$

Rearranging this equation in terms of n gives

$n=\left[z_{crit}\times \dfrac{\sigma}{M}\right]^2$

Now the Margin of Error is reduced by 2 so the new M_2 is given as M/2 so the value of n_2 is calculated as

$n_2=\left[z_{crit}\times \dfrac{\sigma}{M_2}\right]^2\\n_2=\left[z_{crit}\times \dfrac{\sigma}{M/2}\right]^2\\n_2=\left[z_{crit}\times \dfrac{2\sigma}{M}\right]^2\\n_2=2^2\left[z_{crit}\times \dfrac{\sigma}{M}\right]^2\\n_2=4\left[z_{crit}\times \dfrac{\sigma}{M}\right]^2\\n_2=4n$

As n is given as 40 so the new sample size is given as

$n_2=4n\\n_2=4*40\\n_2=160$

So the sample size to obtain the desired margin of error is 160.

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3 years ago