Answer:
The minimum score required for an A grade is 83.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 72.3 and a standard deviation of 8.
This means that 
Find the minimum score required for an A grade.
This is the 100 - 9 = 91th percentile, which is X when Z has a pvalue of 0.91, so X when Z = 1.34.
The minimum score required for an A grade is 83.
Y-Intercept= -9
Your equation is Y=mx+b, and b is the Y-Intercept
Answer:
Ang SAgot ay pukingina ka
5/9 because 15 + 12 = 27 and 15 are sunroofs so 15/27, I would simplify it to 5/9 but you can either have
15/27 or 5/9
Step-by-step explanation:
14)
Simplifying
3m + 5 = 4m -10
Reorder the terms:
5 + 3m = 4m -10
Reorder the terms:
5 + 3m = -10 + 4m
Solving
5 + 3m = -10 + 4m
Solving for variable 'm'.
Move all terms containing m to the left, all other terms to the right.
Add '-4m' to each side of the equation.
5 + 3m + -4m = -10 + 4m + -4m
Combine like terms: 3m + -4m = -1m
5 + -1m = -10 + 4m + -4m
Combine like terms: 4m + -4m = 0
5 + -1m = -10 + 0
5 + -1m = -10
Add '-5' to each side of the equation.
5 + -5 + -1m = -10 + -5
Combine like terms: 5 + -5 = 0
0 + -1m = -10 + -5
-1m = -10 + -5
Combine like terms: -10 + -5 = -15
-1m = -15
Divide each side by '-1'.
m = 15
Simplifying
m = 15
(thank to <em>geteasysolution</em> . com
15)
xy+yz=xz
a+a+8=50
2a=42
a=21
a+8=29
