2 years ago

Help with evaluate and graph PLEASE HURRY

Mathematics

1 answer:

elixir [45]2 years ago

3 0

Answer:

Box 1 = -1

Box 2 = 8

Box 3 = 14

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Find the zeros of y = x + 6x- 4 by completing the square.

dsp73

Answer:

$\large\boxed{x=-3\pm\sqrt{13}}$

Step-by-step explanation:

$(a+b)^2=a^2+2ab+b^2\qquad(*)\\\\\\x^2+6x-4=0\qquad\text{add 4 to both sides}\\\\x^2+2(x)(3)=4\qquad\text{add}\ 3^2=9\ \text{to both sides}\\\\\underbrace{x^2+2(x)(3)+3^2}_{(*)}=4+9\\\\(x+3)^2=13\Rightarrow x+3=\pm\sqrt{13}\qquad\text{subtract 3 from both sides}\\\\x=-3\pm\sqrt{13}$

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Solve 11 and 13 pleaseeeee

nata0808 [166]

32 degees, 43.8 degrees, 53.8, 63.8 Yes they are proportional

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2 years ago

How<br> Do you graph 2x+8y=-32

Neporo4naja [7]

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2 years ago

1) What are the solutions of the equation? x^2 – 3x = 28?<br><br> Asap please . 30 points

Sedbober [7]

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2 years ago

Read 2 more answers

List all the factors of 18

-Dominant- [34]

1 and 18
2 and 9
3 and 6 or of you want the set
1,2,3,6,9,18

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2 years ago