<h2><u>
Answer With Explanation:</u></h2>
<u>Firstly, let's start with <XOZ: =55°</u>
We know that <ZOQ is 70° and angles on a line add up to 180° so we do 180-70=110 110 divided by 2 = 55 so the 2 angles (XOZ & XOP are 55)
<u>Secondly, <OMN, <MON & <ONM = All are 60°</u>
These 2 angles are joined to create an equilateral triangle which always adds up to 180°
So, there are 3 points to this triangle, therefore we divide 180 by 3 which is 60. The angles are 60°
<u>Thirdly, <QON: =55°</u>
This angle lies on the line XON which needs to add up to 180°
As we worked out before, <XOZ was 55°
So, <ZOQ was already given as 70°
We then do 55+70=125 then 180-125=55°
<QON is 55°
(I'm only in Grade 9 LOL)
You divide 29:11= 2 7/11
so you have 2 full vans and one with 7 students.
so the answer is 7
28 to 16
Divide both numbers by 4.
7 to 4
I believe the answer is 9.8
Answer:
(b – 8)(b + 4)
Step-by-step explanation:
The signs of the binomial constants must be different in order for their product to be -32.
The one with the larger magnitude must be negative in order for their sum to be -4. The only viable choice is (b -8)(b +4).
