the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
The length, width, and height In the most common contexts in elementary school, mathematics does not have a formal definition for these terms, nor does it have rules about "proper" use.
F you just want to see the really short way, just skip down to AAAAAAAAAAAA
so, here is the long explanation
exponential properties
don't forget pemdas
2x^2=2(x^2)
so
=
AAAAAAAAAAAAAAAAAAAAAAAA
so we see
the original equatio is
remember
so we can seperate the constants
we know that the placeholders cannot affet the position of the constants unless they are grouped together which they are not
terfor the answer must have 2/3 in it
the only one that hsa that is A
ANSWER IS A
Answer: 35 apples are ripe and rest i.e 21 apples are not.
Step-by-step explanation:
5/8 of 56 apples are ripe i.e 35 apples are ripe and the rest 56-35 apples are not.
Mark me brainliest.