All categories

2 years ago

Can someone help me? Pleaseeeee

Mathematics

1 answer:

Gennadij [26K]2 years ago

6 0

Answer:

a. x = 82 degrees

b. All angles less than 90 degrees are 65 degrees and 33 degrees and 82 degrees in an acute triangle.

Step-by-step explanation:

A triangle has to equal to 180 degrees, add 65 and 33 together to get 98 degrees, subtract 180 from 98 to get 82 degrees. Part B is self explanatory.

You might be interested in

I arranged my books so that I had the same number of books on each of my 4 shelves. If each shelf has 16 books on it, how many b

Doss [256]

Answer:

64 books

Step-by-step explanation:

4 0

2 years ago

Dy/dx = 2xy^2 and y(-1) = 2 find y(2)

Anarel [89]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2887301

—————

Solve the initial value problem:

dy
——— = 2xy², y = 2, when x = – 1.
dx

Separate the variables in the equation above:

$\mathsf{\dfrac{dy}{y^2}=2x\,dx}\\\\
\mathsf{y^{-2}\,dy=2x\,dx}$

Integrate both sides:

$\mathsf{\displaystyle\int\!y^{-2}\,dy=\int\!2x\,dx}\\\\\\
\mathsf{\dfrac{y^{-2+1}}{-2+1}=2\cdot \dfrac{x^{1+1}}{1+1}+C_1}\\\\\\
\mathsf{\dfrac{y^{-1}}{-1}=\diagup\hspace{-7}2\cdot \dfrac{x^2}{\diagup\hspace{-7}2}+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{y}=x^2+C_1}$

$\mathsf{\dfrac{1}{y}=-(x^2+C_1)}$

Take the reciprocal of both sides, and then you have

$\mathsf{y=-\,\dfrac{1}{x^2+C_1}\qquad\qquad where~C_1~is~a~constant\qquad (i)}$

In order to find the value of C₁ , just plug in the equation above those known values for x and y, then solve it for C₁:

y = 2, when x = – 1. So,

$\mathsf{2=-\,\dfrac{1}{1^2+C_1}}\\\\\\
\mathsf{2=-\,\dfrac{1}{1+C_1}}\\\\\\
\mathsf{-\,\dfrac{1}{2}=1+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-1=C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-\dfrac{2}{2}=C_1}$

$\mathsf{C_1=-\,\dfrac{3}{2}}$

Substitute that for C₁ into (i), and you have

$\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}}\\\\\\
\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}\cdot \dfrac{2}{2}}\\\\\\
\mathsf{y=-\,\dfrac{2}{2x^2-3}}$

So y(– 2) is

$\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot (-2)^2-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot 4-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{8-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{5}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: <em>ordinary differential equation ode integration separable variables initial value problem differential integral calculus</em>

7 0

2 years ago

What is the equation of the line, in point-slope form, that passes through the points (4, 8) and (2,-2)?

Annette [7]

Answer:

y = 5x -12

Step-by-step explanation:

point-slope form:

y - y1 = m(x-x1)

m= slope

m= (y2-y1)/ (x2-x1)

we have (4, 8) and (2,-2)

x1 = 4 y1= 8

x2= 2 y2= -2

m=( -2-8) / (2- 4)

m= -10/ -2

m= 5

so we have:

y - 8 = 5(x-4)

y - 8= 5x -20

y= 5x -20 +8

y = 5x -12

3 0

2 years ago

What is the prime number 14 13 21 33

kvv77 [185]

Answer:

13 is the prime number

Step-by-step explanation:

Nothing can multiply to produce 13

8 0

2 years ago

Identify this conic section. x 2 + y 2 = 25 line circle ellipse parabola hyperbola

patriot [66]

Answer:

circle

Step-by-step explanation:

The equation

x² + y² = r²

Represents a circle centred at the origin with radius r

x² + y² = 25 ← is in this form and

is a circle centre (0, 0) with r = 5

7 0

2 years ago

Read 2 more answers