34960 × 2.5% = 1748 + 445 = 2,193 for the week (:
Answer:
Here you go :)
Step-by-step explanation:
(2 1/3)(3 3/4)
= 7/3(3 3/4)
= 7/3(15/4)
= 35/4
= 8 3/4
I hope this helps, if it doesn't then just message me and ill be more than happy to help :)
To solve this problem, we make use of the z statistic. The
formula for z score is:
z = (x – μ) / s
where,
x = is the sample score = 21 or higher
μ = the population mean = 20.8
s = the standard deviation = 4.8
Solving for the z score:
z = (21 – 20.8) / 4.8
z = 0.0417
Next step to do is to find for the p value using the
standard distribution tables at z = 0.04. Since we are looking for the
probability of getting 21 or higher, therefore this is a right tailed test,
hence
p = 0.516
<span>So there is about 51.6% that a student will get a score of
21 or greater.</span>
Answer:
The group's claim is not supported at 1% significance level.
Step-by-step explanation:
given that a local group claims that the police issue more than 60 speeding tickets a day in thire area
The data they collected for 2 weeks is given below:
70 48 41 68 69 55 70
57 60 83 32 60 72 58
Std error of mean = 
(Right tailed test at 1% significance level)
Mean difference = 0.10
Test statistic t with df 13 = mean difference/std error
= 0.029
p value = 0.4886
Since p >0.01, we accept null hypothesis
The group's claim is not supported at 1% significance level.
