we know that
For a polynomial, if
x=a is a zero of the function, then
(x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.
So
In this problem
If the cubic polynomial function has zeroes at 2, 3, and 5
then
the factors are
Part a) Can any of the roots have multiplicity?
The answer is No
If a cubic polynomial function has three different zeroes
then
the multiplicity of each factor is one
For instance, the cubic polynomial function has the zeroes
each occurring once.
Part b) How can you find a function that has these roots?
To find the cubic polynomial function multiply the factors and equate to zero
so
therefore
the answer Part b) is
the cubic polynomial function is equal to
Answer:
8 1/3 cubes
Step-by-step explanation:
The correct answer is: [D]: " x² – 5x – 24 " .
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Explanation:
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Given: " (x + 3)(x – 8) " ; expand :
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Note: (a + b) (c + d) = ac + ad + bc + bd .
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a = x ;
b = 3 ;
c = x
d = 8
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" (x + 3)(x – 8) " ;
= (x * x) + ( -8 * x) + ( 3 * x ) + (3 * -8) ;
= x² + (-8x) + 3x + (-24) ;
= x² – 8x + 3x – 24 ;
→ Combine the "like terms" :
– 8x + 3x = – 5x ;
And simplify the expression;
to get:
→ " x² – 5x – 24 " ; which is: Answer choice: [D]: " x² – 5x – 24 " .
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8 / x = 12 - 3(8)
8 / x = 12 -24
8 / x = -12
x = -0.66666666667
Check your work
8 /(-0.66666666667) = 12- 3(8)
-12 = 12 - 3(8)
-12 = -12
x = -0.66666666667 Exactaly (Ten 6's One 7)
Hope this helps :)