Answer:
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Explanation:
Answer:
11.2 M
Explanation:
Given data:
Number of moles = 6.7 mol
Volume of solution = 0.6 L
Concentration /Molarity = ?
Solution:
Molarity:
It is number of moles of solute in to per kg or litters of solution. It can be calculated by the following formula.
Molarity = number of moles / Volume in L
Now we will put the values in formula.
Molarity = 6.7 mol / 0.6 L
Molarity = 11.2 mol/L
Molarity = 11.2 M
A covalent bond that forms a compound.
<u>Answer:</u> The freezing point of solution is 2.6°C
<u>Explanation:</u>
To calculate the depression in freezing point, we use the equation:
Or,
where,
=
Freezing point of pure solution = 5.5°C
i = Vant hoff factor = 1 (For non-electrolytes)
= molal freezing point depression constant = 5.12 K/m = 5.12 °C/m
= Given mass of solute (anthracene) = 7.99 g
= Molar mass of solute (anthracene) = 178.23 g/mol
= Mass of solvent (benzene) = 79 g
Putting values in above equation, we get:
Hence, the freezing point of solution is 2.6°C