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2 years ago

What is the difference between what happens to the light waves when they reach the "golden" colored mask

Physics

2 answers:

Yuri [45]2 years ago

4 0

Answer:

Explanation:

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Natasha_Volkova [10]2 years ago

3 0

Answer:

I believe the black mask absorbs all light while the golden absorbs everything but whatever color it is that makes a golden hue.

Explanation:

This is because black is void of all colors. when something has a certain pigment, you immediately know that all colors are absorbed acept for the one you can see because it reflects off of it and the waves hit your eyes just right, making it come off as that color. (I believe)

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Which of the following is formed by constructive erosion? 1. delta 2. gully 3. rill 4. glacier

lana [24]

1. Delta, is formed by constructive erosion.

7 0

2 years ago

A rocket initially at rest accelerates at a rate of 99. 0 meters/second2. Calculate the distance covered by the rocket if it att

creativ13 [48]

The rocket will cover $1 \times 10^3\rm \ m$ distance in 4. 5 s. Acceleration can be defined as the change in velocity.

<h3>What is acceleration?</h3>

Acceleration can be defined as the change in speed or the direction of the object.

From kinamatic equation:

$D = v_{t} +\dfrac 12at^2$

Where,

$D$ - final velocity = 445 m/s

$v_0$ - initial valocity = 0 m/s

$a$ - acceleration = 99. 0 m/s²

$t$ - time = 4. 50 s

Put the values in the formula,

$D = 0\times ( 4.5) + \dfrac12\times (99)(4.5)^2\\\\D = 1002 {\rm \ m}\\\\D = 1 \times 10^3\rm \ m$

Therefore, the rocket will cover $1 \times 10^3\rm \ m$ distance in 4. 5 s.

Learn more about Acceleration :

brainly.com/question/2697545

7 0

2 years ago

A car travels around a level, circular track that is 750m across. What coefficient of friction is required to ensure the car can

Crank

The coefficient of friction must be 0.196

Explanation:

For a car moving on a circular track, the frictional force provides the centripetal force needed to keep the car in circular motion. Therefore, we can write:

$\mu mg = m\frac{v^2}{r}$

where the term on the left is the frictional force acting between the tires of the car and the road, while the term on the right is the centripetal force. The various terms are:

$\mu$ is the coefficient of friction between the tires and the road