3x and 2x are alike terms, as they have the same variable
Answer:
(7, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
x = 2y + 5
x/3 - y = 4/3
<u>Step 2: Solve for </u><em><u>y</u></em>
- Substitute: (2y + 5)/3 - y = 4/3
- Multiply 3 on both sides: 2y + 5 - 3y = 4
- Combine like terms: -y + 5 = 4
- Isolate <em>y</em> term: -y = -1
- Isolate <em>y</em>: y = 1
<u>Step 3: Solve for </u><em><u>x</u></em>
- Define: x = 2y + 5
- Substitute: x = 2(1) + 5
- Multiply: x = 2 + 5
- Add: x = 7
And we have our final answer!
The answer would be 2.4*10^5 miles
Answer:
<h2><em>
π/12 rad and 23π/12 rad</em></h2>
Step-by-step explanation:
Given the expression cos(2β)=√3/2 for 0≤β<2π, we are to find the value of β within the range that satisfies the equation.
Since cos id positive in the 4th quadrant, 
, 
Hence the value of 
that satisfy the equation are 15° and 345°
Converting to radians;
180° = πrad
15° = 15π/180 rad
15° = π/12 rad
345° = 345π/180
345° = 23π/12 rad
<em>The values in radians are π/12 rad and 23π/12 rad</em>
Answer:after an hour i think it's at the sea
Step-by-step explanation:
