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2 years ago

What is the best use of an atomic model to explain the charge of the particles in Thomason beans

1 answer:

5 0

An atom's negative particles are surrounded by positive matter, so the positive particles are easier to remove. Thomson's atom model is formed by positive and negative particles The positive particles are bigger than the negative，but the atom is still in equilibrium，this is possible because they have the same“density if you wanna call it like that。So，the properties of negative particles allow them to move free。On the other hand，bigger particles，don't have free moving like negative particles。That's why electrons（negative particles）are the definition of electricity，because they can move easily，although this movement depend on the material，metal are better to move in than wood or plastic.

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The tires of a car make 75 revolutions as the car reduces its speed uniformly from 95 km/hr to 55 km.hr. the tires have a diamet

sveta [45]

<span>95 km/h = 26.39 m/s (95000m/3600 secs) 55 km/h = 15.28 m/s (55000m/3600 secs) 75 revolutions = 75 x 2pi = 471.23 radians radius = 0.80/2 = 0.40m v/r = omega (rad/s) 26.39/0.40 = 65.97 rad/s 15.28/0.40 = 38.20 rad/s s/((vi + vf)/2) = t 471.23 /((65.97 + 38.20)/2) = 9.04 secs (vf - vi)/t = a (38.20 - 65.97)/9.04 = -3.0719 The angular acceleration of the tires = -3.0719 rad/s^2 Time is required for it to stop (0 - 38.20)/ -3.0719 = 12.43 secs How far does it go? 65.97 - 38.20 = 27.77 M</span>

7 0

2 years ago

A 200 kg weather rocket is loaded with 100 kg of fuel and fired straight up. It accelerates upward at 35 m/s2 for 35 s , then ru

r-ruslan [8.4K]

Answer:

T = 295.57 s

Explanation:

given,

mass of the rocket = 200 Kg

mass of the fuel = 100 Kg

acceleration = 35 m/s²

time, t = 35 s

time taken by the rocket to hit the ground, = ?

Final speed of the rocket when fuel is empty

using equation of motion

v = u + a t

v = 0 + 35 x 35

v = 1225 m/s

height of the rocket where fuel is empty

v² = u² + 2 a s

1225² = 0 + 2 x 35 x h₁

h₁ = 21437.5 m

After 35 s the rocket will be moving upward till the final velocity becomes zero.

Now, using equation of motion to find the height after 35 s

v² = u² + 2 g h₂

0² = 1225² + 2 x (-9.8) h₂

h₂ = 76562.5 m

total height = h₁ + h₂

= 76562.5 m + 21437.5 m = 98000 m

now, time taken by before the rocket hit the ground

using equation of motion

$s = u t +\dfrac{1}{2}at^2$

$-13500 = 1225 t -\dfrac{1}{2}\times 9.8 \times t^2$

negative sign is used because the distance travel by the rocket is downward.

4.9 t² - 1225 t - 13500 = 0

$t = \dfrac{-(-1225)\pm \sqrt{1225^2 - 4\times 4.9 \times (-13500)}}{2\times 4.9}$

t = 260.57 s

neglecting the negative sign

total time the rocket was in air

T = t₁ + t₂

T = 35 + 260.57

T = 295.57 s

Time for which rocket was in air is equal to 295.57 s.

6 0

2 years ago

If the car travels thrice(3times) around the track,who much is the total distance covered?

Katyanochek1 [597]

What does thrice mean not being mean or anything just saying so I can help with the question

5 0

2 years ago

Paul sprinkles iron filings onto a piece of paper

Ksivusya [100]

Answer:

The other one

Explanation:

6 0

2 years ago

An object has a mass of 4kg and an average acceleration of 10m/s/s what is the force

Alisiya [41]

Force = mass x acceleration
Force = 4kg x 10m/s^2
Force = 40N

4 0

2 years ago