<span>polyunsaturated!!! Hope this helps mark this the brainliest!</span>
The of melting point of gold is 1,948 degrees F and 1,064 degrees C
<span>The boiling point is 4,892 degrees F and 2,700 degrees C
Yet the numbers neutrons are 12. The number of protons is 36 and electrons is the same as protons
hope this helped :)
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Of Ok here is what I am thinking.
Simple replacement means when one element or compound moves out of another element and is replaced by this compound.
For example if you have A+BC ----- AC + B
Most of the time the one which is replaced is found on the right and the left one is going be only one element or compound.
Double replacement means when the two compounds exchange the positive and negative ions. Ok let see this example:
AB+ CD------- AD+ BC
this means if A have + sign and D has - sign they will share to form new compound the same is true for DC. Don't forget that all compounds are formed from positive and negative ions.
QUESTIONS
CUSO4 + NA2S---- CUS + Naso4[ double replacement]
KBR +Pb[CLO3]2------K[clo3]2 +PbBr [ double replacement]
I do not think these questions can be single replacement.
I hope this may helps you.
Liquid, solid, and gas are all different substances
Answer:
The volume of the solution is 0.305 liters.
Explanation:
Molar mass is the amount of mass that a substance contains in one mole. The molar mass of K₂Cr₂O₇ is 294 g / mole. Then you can apply the following rule of three: if by definition of molar mass 294 grams of the compound are contained in 1 mole, 180 grams are contained in how many moles?
moles= 0.61
Molarity is a measure of the concentration of a substance that is defined as the number of moles contained in a certain volume. So, the molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:
Molarity is expressed in units .
In this case:
- molarity= 2 M
- number of moles of solute= 0.61 moles
- volume= ?
Replacing in the definition of molarity:
Solving:
volume= 0.305 liters
<u><em>The volume of the solution is 0.305 liters.</em></u>