1.00 would be your answer because 95 rounded up is 100. So, 0.95 is closest to 1.00
Answer: 13300
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Work Shown:
A = event that it rains
B = event that it does not rain
P(A) = 0.30
P(B) = 1-P(A) = 1-0.30 = 0.70
Multiply the attendance figures with their corresponding probabilities
- if it rains, then 7000*P(A) = 7000*0.30 = 2100
- if it doesn't rain, then 16000*P(B) = 16000*0.70 = 11200
Add up the results: 2100+11200 = 13300
This is the expected value. This is basically the average based on the probabilities. The average is more tilted toward the higher end of the spectrum (closer to 16000 than it is to 7000) because there is a higher chance that it does not rain.
me neither but this is what i got
3n² p⁴
296/21 is the answer hope this helps
Answer:
The answer is the second option
Step-by-step explanation:
Let u=x^2.
Set this equal to x^2
or
or
