The sum of the sum notation ∞Σn=1 2(1/5)^n-1 is S= 5/2
<h3>How to determine the sum of the notation?</h3>
The sum notation is given as:
∞Σn=1 2(1/5)^n-1
The above notation is a geometric sequence with the following parameters
- Initial value, a = 2
- Common ratio, r = 1/5
The sum is then calculated as
S = a/(1 - r)
The equation becomes
S = 2/(1 - 1/5)
Evaluate the difference
S = 2/(4/5)
Express the equation as products
S = 2 * 5/4
Solve the expression
S= 5/2
Hence, the sum of the sum notation ∞Σn=1 2(1/5)^n-1 is S= 5/2
Read more about sum notation at
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Get rid of negative exponents by remembering that x^-a= 1/x^a.
6^-3= 1/6^3
Evaluate the exponent
6^3= 216
Final answer: 1/216
The scale factor is 3 as the lengths in the bigger triangle when divided by 3 gives the lengths in the smaller triangle
5/10 bc it is equal to 1/2 which is bigger than 2/5 or 4/10 1/3
Step-by-step explanation:
60% of 20 = 12