We know that
a(n)=4n+1
To find the sum of the first n<span> terms of an arithmetic series
use the formula
</span><span><span>Sn</span>=<span>n(<span>a1</span> + <span>an</span>)/2
</span></span>a1--------------> is the first term
an--------------> is the last term
n--------------- > <span>is the number of terms
</span>we have that
a1------------> 4*(1)+1=5
a30----------> 4*(30)+1=121
n------------- > 30
S30=30*(5 + 121)/2=1890
the answer is 1890
Answer:
(x + y)² = 25
Step-by-step explanation:
The expansion of (x + y)² is
(x + y)² = x² + y² + 2xy ← substitute x² + y² = 15 and xy = 5
= 15 + 2(5)
= 15 + 10
= 25
Answer:
b2 = 1
Step-by-step explanation:
A = h(b1 + b2)
Given:
A = 16
h = 4
b1 = 3
b2 = x
Work:
A = h(b1 + b2)
16 = 4(3 + x)
16 = 12 + 4x
4x = 16 - 12
4x = 4
x = 1
Answer:
534
Step-by-step explanation:
Answer:
4m
Step-by-step explanation:
It would be 4m as there are four different copies and the variable being used originally is 'm'. Therefore, we can move it around and since multilication is d addtiion, we would correct this to 4m.
