All categories

2 years ago

Shayna sold 6 French silk cheesecakes and 6

Mathematics

1 answer:

Lena [83]2 years ago

3 0

One French silk is $11 and the strawberry cheesecakes are also $11

You might be interested in

Use partial products to multiply 2,104 x 8. 2,104 32 8 x 4 ones 0 8 x 0 tens N 1 hundreds 8 x 2 thousands - 16.000

xeze [42]

9514 1404 393

Answer:

16832

Step-by-step explanation:

As your problem statement says, ...

2104 × 8 = 4×8 +00×8 +100×8 +2000×8

= 32 +0 +800 +16000

= 16,832

7 0

2 years ago

Item 1 A bag contains 7 blue cards, 4 green cards, 6 red cards, and 8 yellow cards. You randomly choose a card. a. How many poss

egoroff_w [7]

Answer:

4 possible outcomes

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.

The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

Let

x------> size of the event space

y-----> size of the sample space

$P=\frac{x}{y}$

In this problem

The probability of choose a blue card is

$x=7$

$y=7+4+6+8=25$

substitute

$P=\frac{7}{25}$

The probability of choose a green card is

$x=4$

$y=7+4+6+8=25$

substitute

$P=\frac{4}{25}$

The probability of choose a red card is

$x=6$

$y=7+4+6+8=25$

substitute

$P=\frac{6}{25}$

The probability of choose a yellow card is

$x=8$

$y=7+4+6+8=25$

substitute

$P=\frac{8}{25}$

The sum of the probabilities of the 4 possible outcomes is equal to

$\frac{7}{25}+\frac{4}{25}+\frac{6}{25}+\frac{8}{25}=\frac{25}{25}$ ----> represent the 100%

4 0

2 years ago

How do you convert a fraction to a percent

Lubov Fominskaja [6]

To convert from a fraction to a percent,
You just need to divide the fractions then multiply the product by 100.

Examples:
1. What is 3/4 in percent?
a. 3/4 = 0.75 x 100 = 75%
b. 45/98 = 0.46 x 100 = 46&
c. 60/100 = 0.6 x 100 = 60%
d. 1/5 = 0.2 x 100 = 20&
e. 6/99 = 0.06 x 100 = 6%

3 0

2 years ago

Sketch the equilibrium solutions for the following DE and use them to determine the behavior of the solutions.

GREYUIT [131]

Answer:

$y=\dfrac{1}{1-Ke^{-t}}$

Step-by-step explanation:

Given

The given equation is a differential equation

$\dfrac{dy}{dt}=y-y^2$

$\dfrac{dy}{dt}=-(y^2-y)$

By separating variable

⇒ $\dfrac{dy}{(y^2-y)}=-t$

$\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-dt$

Now by taking integration both side

$\int\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-\int dt$

⇒ $\ln (y-1)-\ln y=-t+C$

Where C is the constant

$\ln \dfrac{y-1}{y}=-t+C$

$\dfrac{y-1}{y}=e^{-t+c}$

$\dfrac{y-1}{y}=Ke^{-t}$

$y=\dfrac{1}{1-Ke^{-t}}$

from above equation we can say that

When t will increases in positive direction then $e^{-t}$ will decreases it means that ${1-Ke^{-t}}$ will increases, so y will decreases. Similarly in the case of negative t.

4 0

2 years ago

Find the area of figure 1. a -12 units2 b- 14 units2 c- 8 units2 d- 10 units2

Brilliant_brown [7]

Answer:

Step-by-step explanation:

if you look at the chart. it goes up five and has a width of 2. multiply 5 x 2 = you get 10

3 0

2 years ago

Read 2 more answers