<span>Solubility product constant (Ksp) is </span>applied to the saturated ionic solutions<span> which are in equilibrium with its
solid form. The solid is partially dissociated into its ions.</span><span>
For the BaF, the dissociation as follows;
BaF</span>₂(s) ⇄ Ba²⁺(aq)
+ 2F⁻(aq)
<span>
Hence,
Ksp = [Ba</span>²⁺(aq)] [F⁻(aq)]²
Answer:
B. 
Explanation:
The unit for rate is M/s while the unit for each molecule should be M. You can find the unit for k by putting the units for rate and the molecules into the equation
rate= k{X][Y]
M/s= k * 
* 
k= (M/s) / (
)
k=
You can also use this predetermined formula to solve this problem faster: k= 
Where n is the number of molecule. There are 3 molecule(2X and 1Y) so n=3, so
k=
k= 
= 
=
During the reaction of glucose and fructose with excess phenylhydrazine to form osazone, only the C-1andC-2 atoms of glucose and fructose participate in the reaction. The rest of the molecule remains intact. Hence, glucose and fructose produce the same osazone.
Yes, it will be worthwhile to investigate finding a catalyst to use in this reaction under standard conditions because it is negative.
<h3>What is a Catalyst?</h3>
This is a substance which speeds up the rate of a chemical reaction by lowering the activation energy.
ΔG being negative indicates a a slow reaction which is why a catalyst under standard conditions should be used.
Read more about Catalyst here brainly.com/question/12507566
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