Answer:
Probability that the proportion of airborne viruses in a sample of 529 viruses would be greater than 8% is 0.9545.
Step-by-step explanation:
For the given population the distribution of air-borne viruses is given as 6%. Now for this the value of Z score is given as
Here
- is the sample measure which is 8% or 0.08
- p is the population measure which is 6% or 0.06
- n is the number of samples which is 529
So the Z score is given as
For this the score, the value of probability is calculated from the table as below:
Here value of p(Z<-1.6955) is given as 0.0455
(-2)^4=16
(-2)^-1=-1/2
-1/2x16=-8
Answer: -8
Since my answer was deleted here it is:
The variable x represents the cost per pound of meat.
The variable y represents the cost per pound of cheese.
The deli charges $4.50 for a pound of meat.
Have a great day! (this is late but for anyone else who needs it)
Answer:
130.
Step-by-step explanation:
18 + 4(28(
= 18 + 4 * 28 Multiplication is done before addition so we have:
18 + 112
= 130.