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Find the equation of a line parallel to y-5=6x-10 that passes through (4,10)
❖ If lines are parallel to each other, they have the same slope.
So the slope of the line parallel to y-5=6x-10 is 6.
Now, since we're also given the point crossed by the line, we write the equation in point-slope form:-
Substitute 10 for y₁, 6 for m and 4 for x₁:-
On simplification,
Adding 10 to both sides results in:-
So we conclude that Option A is correct.
<h3>Good luck.</h3>
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Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:
x = -1 ± 2i
Step-by-step explanation:
The standard form of a quadratic equation is ax² + bx + c = 0, and the quadratic formula is x= [−b ± √(b
² - 4ac) ] / 2a
In this case, a = 1, b = 2 and c = 5. Now you have to substitute in the quadratic formula:
x= [−b ± √(b
² - 4ac) ] / 2a
x= [−2 ± √(2
² - 4*1*5) ] / 2*1
x= [−2 ± √(4 - 20) ] / 2
x= [−2 ± √(-16) ] / 2
Since the square root is negative, you have to use imaginary numbers to continue solving the equation. Remmber that √(-1) = i.
x= [−2 ± √(-16) ] / 2
x= [−2 ± √(16)i ] / 2
x= [−2 ± 4i ] / 2
x1 = [−2 + 4i ] / 2
x1 = -1 + 2i
x2 = [−2 - 4i ] / 2
x2 = -1 - 2i
So the answers of x are -1 ± 2i