Answer:
a) 7.5/3=2.5
b) about 3 pieces can be cut.
Step-by-step explanation:
(2x^2-5x)(4x^2-12x+10) = <span>8x^4 - 44x^3 + 80x^2 - 50x
So, the answer is option C.</span>
<h3>
Explanation:</h3>
In the graph x-coordinate represents the number of wind chimes sold and y-coordinate represents the profit Madison earned. If a point is below the x-axis, means it has negative y-coordinate than it represents loss. Points above x-axis should have x-coordinate more than 6 as stated in the question that she started earning profit after selling her first 6 wind chimes. All the points having x-coordinate less than 6 should lie on or below the x-axis.
By the above statement point B is completely wrong. Point C and Point A are also wrong as they both x-coordinate more than 6 but still they are below x-axis.
Point D is the makes most sense here as it has x-coordinate more than 6 and it is above x-axis. This means that when Madison sold 7 wind chimes she was in a profit of $3.75.
I would find the area of the shape as if it were a rectangle (5x9) and then subtract the area of two triangles (1/2x2x2.5)
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²