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1 year ago

8

If you deposit Tsh 4000 into an account paying 9% annual interest compound monthly ,low long until there is Tsh 10000 in the acc

ount?

1 answer:

pav-90 [236]1 year ago

5 0

Answer:

It will take 10.63 years.

Step-by-step explanation:

Giving the following information:

Present value (PV)= $4,000

Future Value (FV)= $10,000

Interest rate (i)= 9% annual compounded

<u>To calculate the time required to reach $10,000, we need to use the following formula:</u>

n= ln(FV/PV) / ln(1+i)

n= number of years

n= ln(10,000 / 4,000) / ln(1.09)

n= 10.63

It will take 10.63 years.

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2 years ago

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Factorise the following.

zepelin [54]

Answer:

Step-by-step explanation:

i). $\frac{48a^3}{6a}=\frac{6\times 8\times a\times a^2}{6a}$

$=\frac{6a}{6a}\times 8a^2$

= 8a²

ii). $\frac{72a^3b^4c^5}{8ab^2c^3}$ = $\frac{8\times 9\times a\times a^2\times b^2\times b^2\times c^2\times c^3}{8ab^2c^3}$

= $\frac{8ab^2c^3}{8ab^2c^3}\times 9a^2b^2c^2$

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8 0

2 years ago

Find an equation of the line perpendicular to the graph of 14x-7y=8 that passing through the point at (-2,5).

MAXImum [283]

Answer:

2x + 4y = 16.

Step-by-step explanation:

14x - 7y = 8

Convert to slope-intercept form:

-7y = -14x + 8

y = 2x - 8/7

The slope is 2 so the line perpendicular to it has a slope of -1/2, so we have:

y = 1/2x + c

This line passes through the point (-2, 5) so:

5 = -1/2* (-2) + c

5 = 1 + c

c = 5 - 1 = 4

So our equation is y = -1/2x + 4.

Convert to standard from

4y = -2x + 16

2x + 4y = 16.

7 0

2 years ago

Hospital records show that a certain surgical procedure takes on an average 111.6 minutes with a standard deviation of 2.8 minut

Arisa [49]

Answer:

At least 37.74% of the procedures takes between 97.6 and 125.6 minutes

Step-by-step explanation:

The percentage is the area of the standard normal distribution curve between the values 97.6 and 125.6

The standard normal variate of the given data is found as

$Z=\frac{X-\overline{X}}{\sigma }$

Thus for the given values Z is calculated as under

$Z_1=\frac{97.6-111.6}{2.8}=-5$

Similarly for the other value we have

$Z_2=\frac{125.6-111.6}{2.8}=5$

Thus the area between the calculated values can be found from standard normal distribution table to be 37.74%

8 0

2 years ago

Which ordered pair is a solution to the system of linear equations 1/2x-3/4y=11/60 and 2/5x+1/6y=3/10

natka813 [3]

ANSWER

$( \frac{2}{3} , \frac{1}{5} )$

EXPLANATION

The first equation is

$\frac{1}{2} x - \frac{3}{4} y = \frac{11}{60} ...(1)$

The second equation is

$\frac{2}{5} x + \frac{1}{6} y = \frac{3}{10} ...(2)$

We want to eliminate y, so we multiply the first equation by

$\frac{4}{5}$

$\frac{4}{5} \times \frac{1}{2} x - \frac{4}{5} \times \frac{3}{4} y = \frac{11}{60} \times \frac{4}{5}$

$\frac{2}{5} x - \frac{3}{5} y = \frac{11}{75} ...(3)$

We now subtract equation (3) from (2)

$(\frac{2}{3} x - \frac{2}{3} x )+ ( \frac{1}{6} y - - \frac{3}{5}y ) =( \frac{3}{10} - \frac{11}{75} )$

$\frac{1}{6} y + \frac{3}{5}y =\frac{3}{10} - \frac{11}{75}$

$\frac{23}{30}y = \frac{23}{150}$

Multiply both sides by

$\frac{30}{23}$

$\implies \: \frac{30}{23} \times \frac{23}{30}y= \frac{23}{150} \times \frac{30}{23}$

$\implies \: y = \frac{1}{5}$

Substitute into the first equation to solve for x .

$\frac{1}{2} x - \frac{3}{4} \times \frac{1}{5} = \frac{11}{60}$

Multiply to obtain

$\frac{1}{2} x - \frac{3}{20} = \frac{11}{60}$

$\frac{1}{2} x = \frac{11}{60} + \frac{3}{20}$

$\frac{1}{2} x = \frac{1}{3}$

Multiply both sides by 2.

$2 \times \frac{1}{2} x =2 \times \frac{1}{3}$

$x = \frac{2}{3}$

The solution is

$( \frac{2}{3} , \frac{1}{5} )$

5 0

2 years ago

Read 2 more answers