Answer:
10
Step-by-step explanation:
Let x =lenght, y = width, and z =height
<span>The volume of the box is equal to V = xyz </span>
<span>Subject to the surface area </span>
<span>S = 2xy + 2xz + 2yz = 64 </span>
<span>= 2(xy + xz + yz) </span>
<span>= 2[xy + x(64/xy) + y(64/xy)] </span>
<span>S(x,y)= 2(xy + 64/y + 64/x) </span>
<span>Then </span>
<span>Mx(x, y) = y = 64/x^2 </span>
<span>My(x, y) = x = 64/y^2 </span>
<span>y^2 = 64/x </span>
<span>(64/x^2)^2 = 64 </span>
<span>4096/x^4 = 64/x </span>
<span>x^3 = 4096/64 </span>
<span>x^3 = 64 </span>
<span>x = 4 </span>
<span>y = 64/x^2 </span>
<span>y = 4 </span>
<span>z= 64/yx </span>
<span>z= 64/16 </span>
<span>z = 4 </span>
<span>Therefor the dimensions are cube 4.</span>
Answer:
B
Step-by-step explanation:
x^2=3x-2(subtract 3x and add 2) x^2-3x+2=0(group) (x-1)(x-2)=0(find x) x=1;x=2
find y values for x values and check:
1^2=1, pair 1:(1,1); 3(1)-2=3-2=1, same pair
2^2=4, pair 2:(2,4); 3(2)-2=6-2=4, same pair
pairs: (1,1);(2,4)
3x=9 is C
4x+12 is A
X+1 is B
+3 || g(x)=2x-1