Answer:
1. In the dispersive model, each strand of both daughter molecules contains a mixture of old and newly synthesized DNA, and in the semiconservative model, each new double helix consists of one old and one new strand.
Explanation: it helps to remember that dispersive means to disperse your DNA molecules! And semi conservative means you keep one of your old strands! Hope this helps!
Answer:
The correct answer is statement d.
Explanation:
In oxidative phosphorylation that takes place in mitochondria, the uncouplers prevent the coupling in between the phosphorylation reactions and electron transport, and therefore, prevent the synthesis of ATP without influencing the ATP synthase and respiratory chain.
The uncoupler always exhibits its influence on the synthesis of ATP. The 2,4-dinitrophenol functions as an uncoupler at the time of oxidative phosphorylation. The NADPH and FAD functions as an electron carrier.
Low blood pressure may cause the net hydrostatic pressure of a capillary
to be less than normal resulting in decreased net filtration pressure.
<h3>What is Pressure?</h3>
This is force applied to a body per unit area and it can be calculated by the
following below:
Pressure = Force/Area
When the net hydrostatic pressure of a capillary is less than normal, the
glomerular blood hydrostatic pressure (GBHP) decreases thereby resulting
in a corresponding decrease in net filtration pressure.
Read more about Filtration pressure here brainly.com/question/10035018
Ovulation
That's when the egg "splits" from the oviduct
Answer:
Prediction is correct.
Explanation:
In the body, transportation of molecules can occur in different ways or mechanism.
An example is by facilitated diffusion.
It is a passive form of transport where carrier proteins shuttle the molecule such as glucose into the cell without using energy.
Glucose being a large molecule is shuttled by glucose carriers across the cell membrane into the cell by facilitated diffusion.
Therefore an increase in the number of glucose carrier means an increase in the rate of glucose transport.
The results will show our prediction was correct.
