A complementary angle is an angle that adds up to 90 degree each and every time. So, therefore the correct formula to use is 90-63=27. Now, you have your answer and can check it twice if you'd like by the formula. Again your answer is 27.

3 0

2 years ago

What is the solution of the following system

AleksAgata [21]

Step-by-step explanation:

8x + 14y = 4 ...1

-6x - 7y = -10 ...2

...2 × 2 in 2 sides of the equation

-12x -14y = -20 ...3

...1 + ...3

8x + 14y +(-12x -14y) = 4 +(-20)

8x + 14y - 12x -14y = 4 - 20

-4x = -16

x = (-16)/(-4)

= 4

replace x in ...1 or ...2 you will reserve y value

and answer in the term of (x,y)

4 0

2 years ago

I need help on these ASAP !!!

liq [111]

Answer:

IDK.

Step-by-step explanation:

Ask ur teacher for help.

I hope this helps u.

7 0

2 years ago

Read 2 more answers

Find the following: F(x, y, z) = e^(xy) sin z j + y tan^−1(x/z)k Exercise Find the curl and the divergence of the vector field.

natulia [17]

$\vec F(x,y,z)=e^{xy}\sin z\,\vec\jmath+y\tan^{-1}\dfrac xz\,\vec k$

Divergence is easier to compute:

$\mathrm{div}\vec F=\dfrac{\partial(e^{xy}\sin z)}{\partial y}+\dfrac{\partial\left(y\tan^{-1}\frac xz\right)}{\partial z}$

$\mathrm{div}\vec F=xe^{xy}\sin z-\dfrac{xy}{x^2+z^2}$

Curl is a bit more tedious. Denote by $D_t$ the differential operator, namely the derivative with respect to the variable $t$ . Then

$\mathrm{curl}\vec F=\begin{vmatrix}\vec\imath&\vec\jmath&\vec k\\D_x&D_y&D_z\\0&e^{xy}\sin z&y\tan^{-1}\frac xz\end{vmatrix}$

$\mathrm{curl}\vec F=\left(D_y\left[y\tan^{-1}\dfrac xz\right]-D_z\left[e^{xy}\sin z\right]\right)\,\vec\imath-D_x\left[y\tan^{-1}\dfrac xz\right]\,\vec\jmath+D_x\left[e^{xy}\sin z}\right]\,\vec k$

$\mathrm{curl}\vec F=\left(\tan^{-1}\dfrac xz-e^{xy}\cos z\right)\,\vec\imath-\dfrac{yz}{x^2+z^2}\,\vec\jmath+ye^{xy}\sin z\,\vec k$

5 0

3 years ago