Answer:
The correct answer is 4.16 grams.
Explanation:
Based on the given information, the concentration of KCl solution is 16 % m/v, which means that 100 ml of the solution will contain 16 grams of KCl.
The molarity of the solution can be determined by using the formula,
M = weight/molecular mass × 1000/Volume
The molecular mass of KCl is 74.6 grams per mole.
M = 16/74.6 × 1000/100
M = 16/74.6
M = 2.14 M
Now the weight of KCl present in the solution of 26 ml will be,
2.14 = Wt./74.6 × 1000 /26
Wt. = 4.16 grams
Answer:
Explanation:
Such types of compounds in which conjugated planer ring system and delocalized pi electrons are present are called aromatic compounds such as Toluene, Benzene and some other. Generally, these compounds follow Huckle's rule. The trisubstituted ring means a compound in which three hydrogen atoms are replaced by three other groups. In the given compound two hydrogen atoms are replaced by two methyl groups and one hydrogen atom is replaced by one Chlorine atom. From the given compound , and can be drawn.
Answer:
Explanation:
Rivers may be contaminated by sewage.
I do hope I helped you! :)
Answer:
built a special cavity where the electromagnetic quantum states resonate with the natural vibrations of the atoms. In doing so, one cancouple a photon-based oscillator to a mechanical oscillator, controlling the mechanical quantum states with visible light. The result is a prototype of a quantum transducer, a device that converts light energy into mechanical energy (sound energy)
Explanation:
Sound energy is created by vibrating particles of medium that propagates as a wave. So in order to convert light (electromagnetic wave) to sound wave it has to be converted into electric or magnetic signals. Then these signals can be converted into sound waves.
However, if you consider the particle nature of light. It contains momentum and after collision sets the other particles into oscillatory motion but the wavelength of these vibrations is too high to be considered as sound waves.
Ne is isoelectronic with Na+ ion.
